ANTILOGARITHMS

 By MR. DEVIDAS MADHAO MISTARI

                               Assistant professor

                                      M.Sc. (physics) 

                                     Material science

HOW TO USE ANTILOGS CALCULATIONS WITH ILLUSTRATIONS.       

        In antilogarithms,if log m = y, then m is called the antilogarithms of y , we can write (AL) antilog y = m.

        We can find antilogs of positive and negative numbers both.

         The antilog of a number y , it has to be expressed into two parts:

(i) Characteristic is positive , negative and zero and

(ii) Mantissa is non-negative four digit number.

For example :

        (1) To find antilog 2.0799  .

                  Here , mantissa is 0799. From the antilog table the number in the row for 0799 is 1200.

                  Characteristic is 2. The decimal point is to be put after (2+1) th i.e., 3rd digit , which is 0.

 therefore AL (2.0799) = 120.0 or 1.200 x 10²

         (2) To find antilog 1.0799  .

                  Here , mantissa is 0799. From the antilog table the number in the row for 0799 is 1200.

                  Characteristic is 1. The decimal point is to be put after (1+1) th i.e., 2nd digit , which is 2.

 therefore AL (1.0799) = 12.00 or 1.200 x 10¹

     (3) To find antilog 0.0799  .

                  Here , mantissa is 0799. From the antilog table the number in the row for 0799 is 1200.

                  Characteristic is 0. The decimal point is to be put after (0+1)th i.e., 1st digit , which is 1.

 therefore AL (0.0799) = 1.200

    (4) To find antilog  bar 1.0799  .

                  Here , mantissa is 0799. From the antilog table the number in the row for 0799 is 1200.

                  Characteristic is bar 1. The decimal point is to be put before  1st digit , which is 1.

 therefore AL (bar 1.0799) = 0.1200  or 1.200 x 10⁻¹

     (5)  To find antilog bar 2.0799  .

                  Here , mantissa is 0799. From the antilog table the number in the row for 0799 is 1200. Characteristic is bar 2

 therefore AL (bar 2.0799) = 0.01200 Or 1.2 x 10⁻²

FIND THE ANTILOG OF NEGATIVE NUMBER    

1) AL(-33.554)

 Adding and subtracting (-1) and (+1)       

   = AL(-33-1+1-0.554)

   = AL(-34+0.446)

   = AL(0.446) x 10⁻³⁴

   = 2.793 x 10⁻³⁴   --- final answer

   +1.000

   -0. 554

⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

  =0.446  

 convertion of negative number to positive number.

2) AL (-0.0624)

Adding and subtracting (-1) and (+1)     

      = AL (-0-1+1-0.0624)

      = AL (-1+1-0.0624)

      = AL (-1+1-0.0624)

      = AL(0.9376) x 10⁻¹

      = 8.662 x 10⁻¹

      = 0.8662   ....final answer

     + 1.0000

     - 0.0624

    ----------------

     = 0.9376    

 convertion of negative number to positive number.

                            *******